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-8000v^2+1484800v-59392000=0
a = -8000; b = 1484800; c = -59392000;
Δ = b2-4ac
Δ = 14848002-4·(-8000)·(-59392000)
Δ = 304087040000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{304087040000}=\sqrt{10485760000*29}=\sqrt{10485760000}*\sqrt{29}=102400\sqrt{29}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1484800)-102400\sqrt{29}}{2*-8000}=\frac{-1484800-102400\sqrt{29}}{-16000} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1484800)+102400\sqrt{29}}{2*-8000}=\frac{-1484800+102400\sqrt{29}}{-16000} $
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